A compound C (molecular formula, C_2H_4O_2) reacts with Na-metal to form a compound R and evolves a gas which burns with a pop sound.

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asked Mar 8, 2018 in Science by shabnam praween (19,050 points) 5 6 8

A compound C (molecular formula, C2H4O2) reacts with Na-metal to form a compound R and evolves a gas which burns with a pop sound. Compound C on treatment with an alcohol A in presence of an acid forms a sweet smelling compound S (molecular formula C3H6O2). On addition of NaOH to C, it also gives R and water. Son treatment with NaOH solution gives back R and A. Identify C, R, A, S and write down the reactions involved.

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answered Mar 8, 2018 by mdsamim (213,225 points) 5 10 15
selected Mar 8, 2018 by shabnam praween
 
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C — Ethanoic acid
R — Sodium salt of ethanoic acid (sodium acetate) and gas evolved is hydrogen
A — Methanol
S — Ester (Methyl acetate)

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