Question

Logx base root3 =6

Answer 1

We know

log x base√3 = log x base 10/ log√3 base 10 = 6 (given)

log x = 6log√3

log x = 6log3^1/2

log x = 6/2log3

log x = 3*0.477

antilog₁₀^(3*0.477) = x

x = antilog₁₀^(3*0.477)

Taking antilog you will get the value of x.