A hollow cone is cut by a plane parallel to the base and the upper portion is removed. If the curved surface of the remainder is 8/9 of the curved

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asked Mar 12, 2018 in Mathematics by Golu (37,045 points) 19 146 419

A hollow cone is cut by a plane parallel to the base and the upper portion is removed. If the curved surface of the remainder is 8/9 of the curved of the whole cone, find the ratio of the line segments into which the altitude of the cone is divided by the plane.

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answered Mar 12, 2018 by faiz (82,347 points) 6 6 11
 
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In Fig. , the smaller cone APQ has been cut off through the plane PQ || BC. Let r and R be the radii of the smaller and larger cone and l and L their slant heights respectively.
Here, in the adjoining figure
OQ = r, MC = R, AQ = l, AC = L.
Now, ΔAOQ ~ ΔAMC
⇒ OQ/MC= AQ/AC
⇒ r/R= l/L

⇒ r=Rl/L         … (i)

Since, curved surface area of the remainder = 8/9 of the curved surface area of the whole cone, therefore, we get,

Hence, the required ratio of their heights = 1:2

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