Without using trigonometric tables, find the value of (sin^2 10° + sin^2 80°)/(sec^2 20°-cot^2 70°)-3tan80°tan 50° tan 45° tan 10° tan 40°.

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answered Mar 12, 2018 by faiz (82,347 points)

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Without using trigonometric tables, find the value of (sin^2 10° + sin^2 80°)/(sec^2 20°-cot^2 70°)-3tan80°tan 50° tan 45° tan 10° tan 40°.

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