Question

In a hydrogen atom, if magnitude of energy of an electron in the ground state is 13.6 ev, then that in the 2nd excited state is ???

Answer 1

We know in a Hydrogen atom, if energy of an electron in ground state is 13.6 eV, then that in the 2nd excited state is 1.51 eV.

Explanation:

Second excited state is the third energy level (i.e n = 3)

So, E₃ = -13.6/(3)² eV

i.e = E₃ = -1.51eV