Ask a Question

What is the remainder when 1^2017+2^2017+3^2017+4^2017 is divided by 2017?

← Prev Question Next Question →
+5 votes
324 views
asked Aug 18, 2016 in Mathematics by Rahul Roy (7,895 points) ● 33 ● 108 ● 286

1 Answer

+3 votes
answered Aug 18, 2016 by vikash (21,277 points) ● 4 ● 19 ● 70
selected Sep 22, 2016 by sarthaks
 
Best answer

The remainder will be zero.

a^n + b^n is divisible by a + b (provided n is odd).

So, 1^2017+2^2017+3^2017+4^2017 will be divisible by (1+2+3+4)

So, it is divisible by 2017 as well.

← Prev Question Next Question →

Related questions

+4 votes
1 answer
Find the remainder when x^51 is divided by x^2-3x+2.
asked Oct 16, 2016 in Mathematics by Rahul Roy (7,895 points)
0 votes
1 answer
4/{9^(1/3 ) - 3^(1/3) + 1} =x, then find the value of x
asked Oct 23, 2016 in Mathematics by Rahul Roy (7,895 points)

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

One Thought Forever

“There is a close connection between getting up in the world and getting up in the morning.“
– Anon
~~~*****~~~

Related questions

© 2017 Sarthaks eConnect
Managed by Sarthaks Digitizing India
...