Find the sum of the first 40 positive integers divisible by 6:

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asked Mar 14, 2018 in Mathematics by paayal (26,720 points) 4 6 52
Find the sum of the first 40 positive integers divisible by 6:

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answered Mar 14, 2018 by sanjaydas (61,430 points) 5 7 7
selected Mar 15, 2018 by faiz
 
Best answer

Solution: a = 6 , d = 6 and n = 40

S40 = 40/2 (12 + 6 x 39) =20 x 336 = 6720

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