Question

For what value of n, are the nth terms of two APs: 63, 65, 67,… and 3, 10, 17,… equal?

Answer 1

Solution: In the first AP a = 63 and d = 2
In the second AP a = 3 and d = 7
As per question,
63+2(n-1) = 2+ 7(n-1)
Or, 61 = 5 (n-1)
Or, n-1 = 61/5
As the result is not an integer so there wont be a term with equal values  for both APs.