Question

In a right triangle ABC right angled at C, P and Q are the points on the sides CA and CB respectively which divides these sides in the ratio 2 : 1. Prove that 9(AQ² + BP²) = 13AB².

Answer 1

[ P and Q divides CA and CB in the ratio 2: 1 respectively]

⇒ 9(AQ² + BP²) = 13 AB2 (Applying Pythagoras Theorem in ΔABC) Hence Proved.