i. Acetophenone and Benzophenone ii. Phenol and Benzoic acid

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asked Mar 19, 2018 in Chemistry by paayal (26,720 points) 4 6 11

Give simple chemical tests to distinguish between the following pairs of compounds:
i. Acetophenone and Benzophenone   ii. Phenol and Benzoic acid
iii. Benzoic acid and ethyl benzoate      iv. Benzaldehyde and acetophenone
v. Ethanal and propanal

1 Answer

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answered Mar 19, 2018 by sanjaydas (61,430 points) 5 7 7
selected Mar 24, 2018 by Vikash Kumar
 
Best answer

Acetophenone and Benzophenone: Acetophenone being a methyl ketone when treated with NaOI (I2 / NaOH) gives yellow precipitate of iodoform whereas benzophenone does not.

ii. Phenol and Benzoic acid: Phenol is a weak acid it does not react with weak base NaHCO3 whereas benzoic acid is a strong acid. It reacts with NaHCO3 to form a sodium salt alongwith evolution of CO2.

iii. Benzoic acid and ethyl benzoate: Benzoic acid is a carboxylic acid and reacts with NaHCO3 to form a sodium salt alongwith evolution of CO2. Ethylbenzoate is an ester. It does not react with NaHCO3.

iv. Benzaldehyde and acetophenone: Benzaldehyde being an aldehyde reduces Tollen’s reagent to shining silver mirror whereas acetophenone being a ketone does not.

v. Ethanal and propanal: Ethanal contains CH3CO group. Hence on treatment with NaOI (I2 / NaOH) gives yellow precipitate of iodoform whereas propanal does not.

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