∫ dx/√(2ax-x^2)=an sin^-1 [x/a^-1]. The value of n is

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asked Mar 20, 2018 in Physics by shabnam praween (19,050 points) 5 6 8

∫ dx/√(2ax-x2)=an sin-1 [x/a-1]. 

The value of n is
(a) 0 

(b)-1

(c)1

(d) none of these.

You may use dimensional analysis to solve the problem

1 Answer

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answered Mar 20, 2018 by santoshjha (25,550 points) 4 5 6
selected Mar 24, 2018 by Vikash Kumar
 
Best answer
The correct answer is

(a) 0

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