Question

A parachutist after bailing out falls 50 m without friction. When parachute opens, it decelerates at 2m/s². He reaches the ground with a speed of 3m/s. At what height, did he bail out?

(a) 293m 

(b) 111m

(c) 91m 

(d) 182m

Answer 1

(a) : Initially, the parachutist falls under gravity
Therefore, u ² = 2ah = 2 × 9.8 × 50 = 980 m ² s ^–2
He reaches the ground with speed
= 3 m/s, a = –2 ms ^–2

Therefore,  (3) ² = u ² – 2 × 2 × h 1
or 9 = 980 – 4 h ₁
or h₁ = 971/4

or h 1 = 242.75 m
Therefore,  Total height = 50 + 242.75
= 292.75
= 293 m.​