A person standing near the edge of the top of a building throws two balls A and B. The ball A is thrown vertically upward and B is thrown vertically ,

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asked Mar 21, 2018 in Physics by shabnam praween (19,050 points) 5 6 75

A person standing near the edge of the top of a building throws two balls A and B. The ball A is thrown vertically upward and B is thrown vertically downward with the same speed. The ball A hits the ground with a speed vA and the ball B hits the ground with a speed vB. We have

(a) vA > vB

(b) vA < vB

(c) vA = vB

(d) the relation between vA and vB depends on height of the building above the ground.

1 Answer

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answered Mar 21, 2018 by santoshjha (25,550 points) 4 5 7
selected Mar 21, 2018 by shabnam praween
 
Best answer

The correct answer is

(c) vA = vB

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