Question

A lift is moving down with acceleration a. A man in the lift drops a ball inside the lift. The acceleration of the ball as observed by the man in the lift and a man standing stationary on the ground are respectively

(a) g, g 

(b) g – a, g – a

(c) g – a, g 

(d) a, g

Answer 1

(c) : For observer in the lift, acceleration = (g – a)
For observer standing outside, acceleration = g.