When forces F1 , F2 , F3 are acting on a particle of mass m such that F2 and F3 are mutually perpendicular, then the particle remains stationary.

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asked Mar 21, 2018 in Physics by paayal (26,720 points) 4 6 11

When forces F1 , F2 , F3 are acting on a particle of mass m such that F2 and F3 are mutually perpendicular, then the particle remains stationary. If the force F1 is now removed then the acceleration of the particle is

(a) F1/m 

(b) F2F3 /mF1

(c) (F2 – F3 )/m 

(d) F2 /m.

1 Answer

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answered Mar 21, 2018 by sanjaydas (61,430 points) 5 7 7
selected Mar 24, 2018 by Vikash Kumar
 
Best answer

(a) : F2 and F3 have a resultant equivalent to F1
 Therefore,  Acceleration = F1/m.
 

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