The block of mass M moving on the frictionless horizontal surface collides with the spring of spring constant K and compresses it by length L.

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asked Mar 21, 2018 in Physics by paayal (26,720 points) 4 6 45
edited Mar 21, 2018 by paayal

The block of mass M moving on the frictionless horizontal surface collides with the spring of spring constant K and compresses it by length L. The maximum momentum of the block after collision is


(a) zero

(b) ML2/K

(c) √(MK)L

(d) KL2/2M

1 Answer

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answered Mar 21, 2018 by sanjaydas (61,430 points) 5 7 7
selected Mar 24, 2018 by Vikash Kumar
 
Best answer

The correct answer is:

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