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A wooden object floats in water kept in a beaker. The object is near a side of the beaker (figure 13-Q4). Let P_1, P_2, P_3 be ,

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asked Mar 26, 2018 in Physics by shabnam praween (19,050 points) ● 5 ● 6 ● 8

A wooden object floats in water kept in a beaker. The object is near a side of the beaker (figure 13-Q4). Let P1, P2, P3 be the pressures at the three points A, B and C of the bottom as shown in the figure.

(a) P1 = P2 = P3.

(b) P1< P2 < P3.

(c)P1 > P2 > P3.

(d) P2 = P3 # P1.

1 Answer

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answered Mar 26, 2018 by santoshjha (25,550 points) ● 4 ● 5 ● 6
selected Mar 27, 2018 by Vikash Kumar
 
Best answer

(a) P1 = P2 = P3.

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