If gE and gM are the accelerations due to gravity on the surfaces of the earth and the moon respectively.

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asked Mar 26, 2018 in Physics by paayal (26,720 points) 4 6 53

If gE and gM are the accelerations due to gravity on the surfaces of the earth and the moon respectively and if Millikan’s oil drop experiment could be performed on the two surfaces, one will find the ratio 

(electronic charge on the moon)/(electronic charge on the earth) to be
(a) gM /gE 

(b) 1

(c) 0 

(d) gE /gM

1 Answer

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answered Mar 26, 2018 by sanjaydas (61,430 points) 5 7 7
selected Mar 28, 2018 by Vikash Kumar
 
Best answer

(b) : Since electronic charge (1.6 × 10–19C) universal constant. It does not depend on g.
Therefore,Electronic  charge on the moon = electronic charge on the earth

or (electronic charge on the moon)/(electronic charge on the earth) = 1.

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