A nucleus with Z = 92 emits the following in a sequence: α, α, β^– , β^– , α, α, α, α, β^– , β^– , α, β^+ , β^+ , α.

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asked Mar 26, 2018 in Physics by paayal (26,720 points) 4 6 11

A nucleus with Z = 92 emits the following in a sequence: α, α, β , β , α, α, α, α, β, β , α, β+ , β+ , α. The Z of the resulting nucleus is

(a) 76 

(b) 78 

(c) 82 

(d) 74.

1 Answer

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answered Mar 26, 2018 by sanjaydas (61,430 points) 5 7 7
selected Mar 28, 2018 by Vikash Kumar
 
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