The repulsive potential energy between the two nuclei is ~ 7.7 × 10^14J.

+1 vote
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asked Mar 26, 2018 in Physics by paayal (26,720 points) 4 6 11

In the nuclear fusion reaction,   given that the repulsive potential energy between the two nuclei is ~ 7.7 × 1014J, the temperature at which the gases must be heated to initiate the reaction is nearly [Boltzmann's constant k = 1.38 × 10–23J/K]

(a) 107

(b) 105

(c) 103

(d) 109K.

1 Answer

0 votes
answered Mar 26, 2018 by sanjaydas (61,430 points) 5 7 7

The correct answer is:

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