Question

With the help of a circuit diagram prove that when a number of resistors are connected in parallel, the reciprocal of equivalent resistance of the combination is equal to the sum of the reciprocals of the individuals resistances of the resistors. Find the resistance between A and B in the following network

Answer 1

If there are two resistances in parallel i.e. R₁ and R₂ . Equivalent resistance R :

1/R=1/R₁ + 1/R₂
Where R1 = 2Ω+ 2Ω = 4Ω
1/R=R₂+ R₁/R₁ R₂
Now R =R₁ R₂/R₁ +R₂
Resistance across A and B :
R =4*4/4+4=16/8 =2Ω