(d) : The uniform rod of length l and mass m is swinging about an axis passing through the end. When the centre of mass is raised through h, the increase in potential energy is mgh. This is equal to the kinetic energy

= (1/2)Iω2.
⇒ mgh = 1/2(m(l2/3)).ω2
Therefore, h = (l2 . ω2)/6g.