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An inductor of inductance L = 400mH and resistors of resistances R1 = 2Ω and R2 = 2Ω.

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asked Mar 27, 2018 in Physics by paayal (26,720 points) ● 4 ● 6 ● 54

An inductor of inductance L = 400mH and resistors of resistances R1 = 2Ω and R2 = 2Ω are connected to a battery of emf 12V as shown in the figure. The internal resistance of the battery is negligible. The switch S is closed at t = 0. The potential drop across L as a function of time is

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answered Mar 27, 2018 by sanjaydas (61,430 points) ● 5 ● 7 ● 7
selected Mar 28, 2018 by Vikash Kumar
 
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(d) : For the given R, L circuit the potential difference across AD = VBC as they are parallel.

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