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Both the strings, shown in figure (15-Q1), are made of same material and have same cross-section. The pulleys are light.

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asked Mar 27, 2018 in Physics by shabnam praween (19,050 points) ● 5 ● 6 ● 8

Both the strings, shown in figure (15-Q1), are made of same material and have same cross-section. The pulleys are light. The wave speed of a transverse wave in the string AB is v1 and in CD it is v2 Then v1 /v2 is

(a) 1

(b) 2

(c)√2

(d) 1/√2.

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answered Mar 27, 2018 by santoshjha (25,550 points) ● 4 ● 5 ● 6
selected Mar 27, 2018 by Vikash Kumar
 
Best answer

The correct answer is

(d) 1/√2.

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