Question

A source emits light of wavelengths 555 nm and 600nm. The radiant flux of the 555 nm part is 40 W and of the 600 nm part is 30 W. The relative luminosity at 600 nm is 0.6. Find (a) the total radiant flux, (b) the total luminous flux, (c) the luminous efficiency.

Answer 1

The radiant flux of 555nm part is 40W and of the 600nm part is 30W
(a) Total radiant flux = 40W + 30W = 70W
(b) Luminous flux = (L.Fllux)_555nm + (L.Flux)_600nm
= 1 × 40× 685 + 0.6 × 30 × 685 = 39730 lumen
(c) Luminous efficiency =Total lumin ous flux / Total radiant flux
=39730 / 70
= 567.6 lumen/W