At 80°C, the vapour pressure of pure liquid A is 520mm of Hg and that of pure liquid B is 1000mm of Hg.

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asked Mar 29, 2018 in Chemistry by paayal (26,720 points) 4 6 48

At 80°C, the vapour pressure of pure liquid A is 520mm of Hg and that of pure liquid B is 1000mm of Hg. If a mixture solution of A and B boils at 80°C and 1 atm pressure, the amount of A in the mixture is (1 atm = 760mm of Hg) 

(a) 50mol percent 

(b) 52mol percent 

(c) 34mol percent 

(d) 48mol percent

1 Answer

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answered Mar 29, 2018 by sanjaydas (61,430 points) 5 7 7
selected Apr 1, 2018 by Vikash Kumar
 
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