The enthalpy changes for the following processes are listed below: Cl2(g) = 2Cl(g) , 242.3kJ mol^–1.

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asked Mar 29, 2018 in Chemistry by paayal (26,720 points) 4 6 11

The enthalpy changes for the following processes are listed below:
Cl2(g) = 2Cl(g) , 242.3kJ mol–1
I2(g) = 2I(g) , 151.0kJ mol–1
ICl(g) = I(g) + Cl(g) , 211.3kJ mol–1
I2(s) = I2(g) , 62.76kJ mol–1
Given that the standard states for iodine and chlorine
are I2(s) and Cl2(g) , the standard enthalpy of formation
for ICl(g) is

(a) –14.6kJ mol–1 

(b) –16.8kJ mol–1

(c) +16.8kJ mol–1 

(d) +244.8kJ mol–1.

1 Answer

0 votes
answered Mar 29, 2018 by sanjaydas (61,430 points) 5 7 7

The correct answer is:

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