Question

The near point and the far point of a child are at 10 cm and 100 cm. If the retina is 2.0 cm behind the eye-lens, what is the range of the power of the eye-lens ?

Answer 1

The child has near point and far point 10 cm and 100 cm respectively.
Since, the retina is 2 cm behind the eye-lens, v = 2cm
For near point u = – 10 cm = – 0.1 m, v = 2 cm = 0.02 m