Question

A wheel rotating at a speed of 600 rpm (revolutions per minute) about its axis is brought to rest by applying a constant torque for 10 seconds. Find the angular deceleration and the angular velocity 5 seconds after the application of the torque.

Answer 1

A wheel rotating at a speed of 600 rpm.
ω₀ = 600 rpm = 10 revolutions per second.
T = 10 sec. (In 10 sec. it comes to rest)
ω = 0
Therefore ω₀ = –αt
α = –10/10 = –1 rev/s2
ω = ω₀ + αt = 10 – 1 × 5 = 5 rev/s.