In this problem the rod has a mass 1 kg
a) πnet = Inet × α
5 × 10 × 10.5 – 2 × 10 × 0.5
= (5 × (1/2)2 + 2 × (1/2)2 + 1/12) × α
15 = (1.75 + 0.084) α
α = 1500/(175 + 8.4) = 1500/183.4 = 8.1 rad/s2 (g = 10)
= 8.01 rad/s2 (if g = 9.8)

b) T1 – m1g = m1a
T1 = m1a + m1g = 2(a + g)
= 2(αr + g) = 2(8 × 0.5 + 9.8)
= 27.6 N on the first body.
In the second body
= m2g – T2 = m2a = T2 = m2g – m2a
= T2 = 5(g – a) = 5(9.8 – 8 × 0.5) = 29 N.
