Given E°Cr^3+/Cr = –0.72V, E°Fe^2+/Fe = –0.42V. The potential for the cell Cr | Cr^3+ (0.1M) | | Fe^2+ (0.01M) | Fe is

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asked Mar 30, 2018 in Chemistry by paayal (26,720 points) 4 6 11

Given E°Cr3+/Cr = –0.72V, E°Fe2+/Fe = –0.42V.
The potential for the cell
Cr | Cr3+ (0.1M) | | Fe2+ (0.01M) | Fe is

(a) –0.26V 

(b) 0.26V

(c) 0.339V 

(d) –0.339V

1 Answer

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answered Mar 30, 2018 by sanjaydas (61,430 points) 5 7 7
selected Apr 1, 2018 by Vikash Kumar
 
Best answer

The correct answer is:

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