A hemispherical portion of the surface of a solid glass sphere (μ = 1.5) of radius r is silvered to make the inner side reflecting.

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asked Mar 30, 2018 in Physics by Nisa (2,540 points) 1 14

A hemispherical portion of the surface of a solid glass sphere (μ = 1.5) of radius r is silvered to make the inner side reflecting. An object is placed on the axis of the hemisphere at a distance 3r from the centre of the sphere. The light from the object is refracted at the unsilvered part, then reflected from the silvered part and again refracted- at the unsilvered part. Locate the final image formed.

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answered Mar 30, 2018 by rubby (7,550 points) 1 3 5
selected Apr 1, 2018 by Vikash Kumar
 
Best answer

As, negative sign indicates images are formed inside APB. So, image should be at C.
So, the final image is formed on the reflecting surface of the sphere.

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