Question

The rate law for a reaction between the substances A and B is given by rate = k[A]ⁿ [B]^m. On doubling the concentration of A and halving the concentration of B, the ratio of the new rate to the earlier rate of the reaction will be as
(a)1/2^{m + n} 

(b) (m + n) 

(c) (n – m) 

(d) 2^{(n – m)}.

Answer 1

On doubling the concentration of A and halving the concentration of B
Rate 2 = k[2A]ⁿ [B/2]^m
Ratio between new and earlier rate