
Let, the parallel beam is first incident on convex lens.
d = diameter of the beam = 5 mm
Now, the image due to the convex lens should be formed on its focus (point B)
So, for the concave lens,
u = +10 cm (since, the virtual object is on the right of concave lens)
f = –10 cm

So, the emergent beam becomes parallel after refraction in concave lens.
As shown from the triangles XYB and PQB,

So, the beam diameter becomes 2.5 mm.
Similarly, it can be proved that if the light is incident of the concave side, the beam diameter will be 1cm.