The figures below depict two situations in which two infinitely long static line charges of constant positive line charge density λ

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asked Mar 31, 2018 in Physics by shabnam praween (19,050 points) 5 6 8

The figures below depict two situations in which two infinitely long static line charges of constant positive line charge density λ are kept parallel to each other. In their resulting electric field, point charges q and – q are kept in equilibrium between them. The point charges are confined to move in the x-direction only. If they are given a small displacement about their equilibrium positions, then the correct statement(s) is (are):

(a) Both charges execute simple harmonic motion.
(b) Both charges will continue moving in the direction of their displacement.
(c) Charge +q executes simple harmonic motion while charge -q continues moving in the direction of its displacement.
(d) Charge -q executes simple harmonic motion while charge +q continues moving in the direction of its displacement

1 Answer

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answered Mar 31, 2018 by santoshjha (25,550 points) 4 5 6
selected Apr 1, 2018 by Vikash Kumar
 
Best answer

As +q is displaced towards right, the repulsion of right side wire will dominate and the net force on +q will be towards left, and vice versa

Hence SHM
For –q, as it is displaced towards right the attraction of right side wire will dominate, which forces the -q charge to move in the same direction of displacement similarity for other side Hence it is not SHM.

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