A mass m = 50 g is dropped on a vertical spring of spring constant 500 N/m from a height h = 10 cm as shown in figure (18-E14).

0 votes
28 views
asked Mar 31, 2018 in Physics by Nisa (2,540 points) 1 12

A mass m = 50 g is dropped on a vertical spring of spring constant 500 N/m from a height h = 10 cm as shown in figure (18-E14). The mass sticks to the spring and

executes simple harmonic oscillations after that. A concave mirror of focal length 12 cm facing the mass is fixed with its principal axis coinciding with the line of motion of the mass, its pole being at a distance of 30 cm from the free end of the spring. Find the length in which the image of the mass oscillates.

1 Answer

0 votes
answered Mar 31, 2018 by rubby (7,550 points) 1 3 5
selected Apr 1, 2018 by Vikash Kumar
 
Best answer

Due to weight of the body suppose the spring is compressed by which is the mean position of oscillation.

From figure B,

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

One Thought Forever

“There is a close connection between getting up in the world and getting up in the morning.“
– Anon
~~~*****~~~

...