Two concave mirrors of equal radii of curvature R are fixed on a stand facing opposite directions.

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asked Mar 31, 2018 in Physics by Nisa (2,540 points) 1 3

Two concave mirrors of equal radii of curvature R are fixed on a stand facing opposite directions. The whole system has a mass m and is kept on a frictionless horizontal table (figure 18-E15).

Two blocks A and B, each of mass m, are placed on the two sides of the stand. At t = 0, the separation between A and the mirrors is 2R and also the separation between B and the mirrors is 2R. The block B moves towards the mirror at a speed v. All collisions which take place are elastic. Taking the original position of the mirrors-stand system to be x = 0 and X-axis along AB, find the position of the images of A and B at t =

(a) R/v (b) 3R/v (c) 5R/v

1 Answer

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answered Mar 31, 2018 by rubby (7,550 points) 1 3 5
selected Apr 1, 2018 by Vikash Kumar
 
Best answer

a) In time, t = R/V the mass B must have moved (v x R/v) = R closer to the mirror stand

b) When t = 3R/v, the block B after colliding with mirror stand must have come to rest (elastic collision) and the mirror have travelled a distance R towards left form its initial position.
So, at this point
of time,

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