The correct answer is (A)
In ccp, O2– ions are 4.
Hence total negative charge = –8
Let Al3+ ions be x, and Mg2+ ions be y.
Total positive charge = 3x + 2y
⇒ 3x + 2y = 8
This relation is satisfied only by x = 2 and y = 1.
Hence number of Al3+ = 2.
and number of Mg2+ = 1.
⇒n = fraction of octahedral holes occupied byAl3+ =2/4=1/2
and m = fraction of tetrahedral holes occupied by Mg2+ =1/8
Hence, answer is (A)