A block is kept on the floor of an elevator at rest. The elevator starts descending with an acceleration

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asked Mar 31, 2018 in Physics by Golu (37,045 points) 19 169 583

A block is kept on the floor of an elevator at rest. The elevator starts descending with an acceleration of 12 m/s 2. Find the displacement of the block during the first 0.2 s after the start. Take g = 10 m/s 2.

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answered Mar 31, 2018 by BISHNU (15,580 points) 4 4 6
selected Apr 1, 2018 by Vikash Kumar
 
Best answer

Because, the elevator is moving downward with an acceleration 12 m/s2 (>g), the bodygets separated. So, body moves with acceleration g = 10 m/s2 [freely falling body] and the elevator move with acceleration 12 m/s2

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