The actinoids exhibit more number of oxidation states in general than the lanthanoids.

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asked Mar 31, 2018 in Chemistry by paayal (26,720 points) 4 6 11

The actinoids exhibit more number of oxidation states in general than the lanthanoids. This is because 

(a) the 5f orbitals extend further from the nucleus than the 4f orbitals 

(b) the 5f orbitals are more buried than the 4f orbitals 

(c) there is a similarity between 4f and 5f orbitals in their angular part of the wave function 

(d) the actinoids are more reactive than the lanthanoids.

1 Answer

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answered Mar 31, 2018 by sanjaydas (61,430 points) 5 7 7
selected Apr 1, 2018 by Vikash Kumar
 
Best answer

(a) : As the distance between the nucleus and 5f orbitals (actinides) is more than the distance between the nucleus and 4f orbitals (lanthanides) hence the hold of nucleus on valence electron decreases in actinides. For this reason the actinoides exhibit more number of oxidation states in general.

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