Ask a Question

[1÷(secA-tanA)]=secA+tanA how to prove

← Prev Question Next Question →
+2 votes
45 views
asked Jun 30, 2017 in Mathematics by Siddarth todi (75 points) ● 1 ● 3

2 Answers

+1 vote
answered Jun 30, 2017 by sarthaks (25,122 points) ● 9 ● 24 ● 36
 
Best answer

Solution:

1/(secA - tanA) 
= (secA + tanA)/[(secA + tanA)(secA - tanA)] 
= (secA + tanA)/(sec2A - tan2A) 
= secA + tanA 

because sec2A - tan2A = 1. 

Proof: 
sin2A + cos2A = 1 
sin2A/cos2A + 1 = 1/cos2A 
tan2A + 1 = sec2A 
1 = sec2A - tan2A

0 votes
answered Jul 1, 2017 by mannu (2,283 points) ● 2 ● 7

this may be another way 

← Prev Question Next Question →

Related questions

0 votes
1 answer
Prove that sinA/(secA+tanA-1)+cotA/(cosecA+cotA-1)=1
asked Feb 15, 2018 in Mathematics by Kundan kumar (49,132 points)
0 votes
1 answer
Prove that (1+cotA-cosecA)(1+tanA+secA)=2
asked Feb 15, 2018 in Mathematics by Kundan kumar (49,132 points)
0 votes
1 answer
Prove that (secA+tanA-1)(secA-tanA+1)=2tanA
asked Feb 15, 2018 in Mathematics by Kundan kumar (49,132 points)

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

One Thought Forever

“There is a close connection between getting up in the world and getting up in the morning.“
– Anon
~~~*****~~~

Related questions

© 2017 Sarthaks eConnect
Managed by Sarthaks Digitizing India
...