kinematics question 5

+2 votes
25 views
asked Jul 16, 2017 in Physics by ankitdixit (1,339 points) 12 50
edited Jul 16, 2017 by Abhishek Kumar

A balloon is moving upwards with velocity 10 ms-1. It releases a stone which comes down to the ground in 11 s. The height of the balloon from the ground at the moment when the stone was dropped is :
(A) 495 m (B) 592 m (C) 460 m (D) 500 m

1 Answer

+1 vote
answered Jul 16, 2017 by Abhishek Kumar (14,593 points) 5 9 35
 
Best answer

A balloon moving upwards with constant velocity 10m/s . if we release the stone from balloon , then, initial speed of stone = 10m/sec .

now, 
initial speed = 10m/sec 
time = 11sec 
let H is the height of balloon when stone is dropped .

use kinematics equation , 
S = Ut + 1/2at² 
-H = 10 × 11 - 1/2 × 10 × (11)² 
= 110 - 5× 121 
= 110 - 605 
= -495 m 
- H = -495 m

hence, H = 495 m 

so, height of balloon is 495m when stone is dropped .

Related questions

+2 votes
1 answer
asked Jul 16, 2017 in Physics by ankitdixit (1,339 points)
+3 votes
1 answer
asked Jul 16, 2017 in Physics by ankitdixit (1,339 points)
+1 vote
1 answer
asked Jul 14, 2017 in Physics by ankitdixit (1,339 points)
0 votes
0 answers
asked Oct 19, 2017 in JEE by RAJEEV R (187 points)
+1 vote
2 answers
asked Oct 19, 2017 in JEE by RAJEEV R (187 points)

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

One Thought Forever

“There is a close connection between getting up in the world and getting up in the morning.“
– Anon
~~~*****~~~

...