Number of moles of MnO4- required to oxidise one mole of ferrous oxalate completely in acidic medium will be:-

Question

A. 7.5 moles

B. 0.2 moles

C. 0.6 moles

D. 0.4 moles

Answer 1

Here is Reaction with Balance

10FeC2O4 + 6KMnO4 + 24H2SO4 ----> 3K2SO4+ 6MnSO4 +  5Fe2(SO4)3 + 24H2O + 20CO2

So we see that

 6 moles of KMnO4 is required to oxidize 10 moles of  FeC2O4 

Then, 1 mole of FeC2O4 would be oxidized by = ?

6/10=0.6