Solve 2 cos2 x + 3 sin x = 0

+1 vote
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asked Aug 10, 2017 in Mathematics by sforrest072 (157,439 points) 61 411 949

1 Answer

+2 votes
answered Aug 10, 2017 by faiz (82,347 points) 6 6 11
selected Aug 10, 2017 by sforrest072
 
Best answer

Solution: The equation can be written as
2(1− sin2 x) + 3sin x = 0
or 2 sin2 x − 3sin x − 2 = 0
or (2sinx +1) (sinx − 2) =0
Hence sin x = -1/2 or sin x = 2
But sin x = 2 is not possible
Therefore sin x = -1/2 = sin 7π/6
Hence, the solution is given by
x = nπ + (-1)n7π/6, where n ∈ Z.

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