Question

What is the volume of 1 g equivalent of ozone at STP

Answer 1

Molecular mass of Ozone(O₃)= 3X16=48gmol^-1

Now, At STP conditions, all gases contain volume=22.4L

Thus at STP, 48g O₃----- 22.4L

1g O₃----- 22.4 / 48 L

thus 1g O₃------ 22.4 X 1 / 48 = 22.4 / 48 L = 0.4667 L

Comments

The answer is not in any option. You might want to recheck it.

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ohh, Now I have edited my answer. There was a silly mistake. Now its right