A compound Fe0.93O1.00, present find out the % of Fe2+ and Fe3+.

+2 votes
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asked Sep 16, 2017 in Chemistry by HariOm Vaja (2,713 points) 4 33 174
Note: Pls give the solution.....

1 Answer

+1 vote
answered Sep 16, 2017 by sforrest072 (157,439 points) 63 448 1286
selected Nov 3, 2017 by HariOm Vaja
 
Best answer

We have Fe3+=x and Fe2+=.93-x

then using charge balance..

3*x+2*(0.93-x)=2*1

( 1 for oxygen)

x=.14

% of Fe3+=(.14/.93)*100=15%

% of Fe2+=(.79/.93)*100=85%

commented Sep 16, 2017 by HariOm Vaja (2,713 points) 4 33 174
How did this method do it?, pls explain what is it
commented Sep 16, 2017 by HariOm Vaja (2,713 points) 4 33 174
Doesn't the question have the rario of Fe per O

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