Correct order of oxidizing strength is:-

Question

Answer 1

Correct Answer is option (4) i.e  MnO₄ ^- > Cr₂O₇ ^2- > VO₂ ⁺

We are given an oxocation (VO₂ ⁺) and two oxoanions (Cr₂O₇ ^2- and MnO₄ ^-) of the transition metals. The ions in which the central metal atom is present in the highest oxidation state will have the highest oxidising power. In VO₂ ⁺, vanadium is present in the +5 oxidation state, while in Cr₂O₇ ^2- ion, Cr is present in the +6 oxidation state. Similarly in the MnO₄ ^-, Mn is present in the +7 oxidation state. Thus as the oxidation state of the central metal atom increases in the order

 V < Cr < Mn

therefore the oxidising power of the oxo ions increases in the order

MnO₄ ^- > Cr₂O₇ ^2- > VO₂ ⁺