The size of isoelectronic species — F – , Ne and Na+ is affected by

+1 vote
42 views
asked Oct 5, 2017 in Chemistry by jisu zahaan (28,760 points) 26 375 813

The size of isoelectronic species — F – , Ne and Na+ is affected by 

(a) Nuclear charge (Z ) 

(b) Valence principal quantum number (n) 

(c) Electron-electron interaction in the outer orbitals 

(d) None of the factors because their size is the same. 

1 Answer

+1 vote
answered Oct 5, 2017 by sforrest072 (157,439 points) 61 410 941
selected Oct 5, 2017 by sanjeev
 
Best answer

The size of an isoelectronic species increases with a decrease in the nuclear charge (Z). For example, the order of the increasing nuclear charge of F– , Ne, and Na+ is as follows: F – < Ne < Na+ Z 9 10 11 Therefore, the order of the increasing size of F– , Ne and Na+ is as follows: Na+ < Ne < F–

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

One Thought Forever

“There is a close connection between getting up in the world and getting up in the morning.“
– Anon
~~~*****~~~

...