Question

A vessel of 120 mL capacity contains a certain amount of gas at 35 °C and 1.2 bar pressure. The gas is transferred to another vessel of volume 180 mL at 35 °C. What would be its pressure?

Answer 1

According to Boyle’s Law P₁ V₁ = P₂ V₂

Here the temperature is constant. Therefore

1.2 X 120 = P₂ X 180

OR

P₂ = 1.2 X 120 /180 = 0.8 bar

Therefore, the pressure would be 0.8 bar.

Answer 2

Given, 

Initial pressure, p1 = 1.2 bar 

Initial volume, V1 = 120 mL 

Final volume, V2 = 180 mL 

Since the temperature remains constant, the final pressure (p2) can be calculated using 

Boyle’s law. 

According to Boyle’s law,