Aluminium reacts with caustic soda in accordance with the reaction
The reaction of aluminium with caustic soda can be represented as:
Therefore volume of hydrogen at STP released when 0.15g of Al reactsv
=0.15 x 3 x 22.4 /54 = 187ml
Now P1 = 1 bar,
P2 = 1 bar
T1 = 273 K
T2 = 20 + 273 = 293 K
V1 = 187 ml
V2 = x
When pressure is held constant,then
V2 = P1 V1 T2 / P2 T1
OR
x = 1 X 187 X 293 / 0.987 X 273
= 201 ml
Therefore, 201 mL of dihydrogen will be released
